TheChillWalrus TheChillWalrus

21-04-2016
Mathematics

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[tex]g(x)=x^3+2x-1[/tex].

texgxx32x1tex class=

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kiev001 kiev001

21-04-2016

First you differentiate it. So:
x^3 + 2x - 1 = 3x^2 + 2
at point (2, 1) the x value is 2 so you substitute that into the differentiated equation.
you get 3(2)^2 + 2 = 14

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