yungcee247 yungcee247
  • 20-03-2019
  • Chemistry
contestada


What would be the pH of a solution whose [OH-] is 2.8 × 10-5M?

Respuesta :

dontewalls17
dontewalls17 dontewalls17
  • 20-03-2019

pOH= - log [OH-]  

pOH=-log[2.8E-5]  

pOH= 4.55  

pOH + pH= 14  

pH= 14 - 4.55  

pH= 9.45

SORRY IF THIS IS WRONG

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