Answer:
The equation has no real solution.
Step-by-step explanation:
[tex]\text{The quadratic formula:}\\\\ax^2+bx+c=0\\\\\Delta=b^2+4ac\\\\if\ \Delta<0,\ then\ the\ equation\ has\ no\ solution\\if\ \Delta=0,\ then\ the\ equation\ has\ one\ solution\ x=\dfrac{-b}{2a}\\if\ \Delta>0,\ then\ the\ equation\ has\ two\ solutions\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\-----------------------------[/tex]
[tex]\text{We have the equation:}\\\\x^2-6x+12=0\\\\a=1,\ b=-6,\ c=12\\\\\Delta=(-6)^2-4(1)(12)=36-48=-12<0[/tex]
