Answer:
There are two solutions one of them = 1 and the other = zero
Step-by-step explanation:
∵ y = -2x + 1 and y = [tex]-2x^{2}[/tex] + 1
∴ To find how many solution we will solve them by equating them
∴ -2x + 1 = [tex]-2x^{2}[/tex] + 1
∴ 2[tex]x^{2}[/tex] - 2x + 1 - 1 = 0
∴ [tex]2x^{2}[/tex] - 2x = 0⇒ take 2x common factor
∴ 2x (x - 1) = 0
∴ 2x = 0 ⇒ x = 0
∴ x - 1 = 0 ⇒ x = 1
∴ The system has two solutions 1 and zero
