hp1000 hp1000
  • 18-02-2019
  • Mathematics
contestada

Part 3
please help
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Part 3 please help class=

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LammettHash
LammettHash LammettHash
  • 18-02-2019

I'm taking "part 3" to mean the 3rd of the posted questions.

If [tex]f(x)=(x^3+2x)\ln x[/tex], then

[tex]f'(x)=(x^3+2x)'\ln x+(x^3+2x)(\ln x)'=(3x^2+2)\ln x+\dfrac{x^3+2x}x[/tex]

[tex]\implies f'(x)=(3x^2+2)\ln x+x^2+2[/tex]

Then when [tex]x=1[/tex], we get [tex]f'(1)=3[/tex].

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