cm74usap2j62s
cm74usap2j62s cm74usap2j62s
  • 19-12-2018
  • Mathematics
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Help me answer this please

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charlotte31519118
charlotte31519118 charlotte31519118
  • 19-12-2018

[tex]66 = (2x - 1) \times (x - 1) \\ 66 = 2 {x}^{2} - 3 + 1 \\ 65 - 2 {x}^{2} + 3x = 0 \\ - 65 + 2 {x}^{2} - 3x = 0 \\ 2 {x}^{2} + 10x - 13x - 65 = 0 \\ 2x \times (x + 5) - 13 \times (x + 5) = 0 \\ (x + 5) \times (2x - 13) = 0 \\ \\ x + 5 = 0 \\ 2x - 13 = 0 \\ \\ x = - 5 \\ x = \frac{13}{2} \\ \\ [/tex]
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