didiconns
didiconns didiconns
  • 16-11-2018
  • Mathematics
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gmany
gmany gmany
  • 20-11-2018

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: [tex]1:2:\sqrt3\to a:2a:a\sqrt3[/tex].

[tex]a=y\\2a=\dfrac{\sqrt2}{3}\\\\a\sqrt3=x\\\\2a=\dfrac{\sqrt2}{3}\qquad\text{divide both sides by 2}\\\\a=\dfrac{\sqrt2}{6}\\\\a\sqrt3=\dfrac{\sqrt2}{6}\cdot\sqrt3=\dfrac{\sqrt6}{6}[/tex]

Answer:

[tex]A)\ x=\dfrac{\sqrt6}{6},\ y=\dfrac{\sqrt2}{6}[/tex]

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