Hello,
Question:
What is the slope of a line that passes through (-12, 15) and (0,4)
Solution:
Formula for slope: [tex]\frac{y2 - y1}{x2 - x1}[/tex]
Put the following coordinates into the formula: [tex]\frac{4 - 15}{0 - (-12)}[/tex]
[tex]\frac{4 - 15}{0 - (-12)} = \frac{4 - 15}{0 + 12}[/tex]
Anytime you have something like this - (-x) its always going to be + x!
Simplify: [tex]\frac{-11}{12}[/tex]
Slope: -11/12
