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  • 19-10-2018
  • Mathematics
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Find [tex]f^-1 ( x ) when f ( x ) = \frac{3x}{x-2}[/tex]

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jimrgrant1 jimrgrant1
  • 19-10-2018

[tex]f^{-1}[/tex](x) = [tex]\frac{2x}{x-3}[/tex]

let y = f(x), then rearrange making x the subject

y = [tex]\frac{3x}{x-2}[/tex] ( multiply both sides by (x - 2 ))

y(x - 2 ) = 3x (distribute )

xy - 2y = 3x ( subtract 3x and add 2y to both sides )

xy - 3x = 2y (factor out x on left side )

x(y - 3 ) = 2y ( divide both sides by (y - 3) )

x = [tex]\frac{2y}{y-3}[/tex]

change y to x for inverse function

[tex]f^{-1}[/tex](x) = [tex]\frac{2x}{x-3}[/tex]



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