Answer:
ΔBLG ≅ ΔPFX
Step-by-step explanation:
Here it is given that ∠B≅<P.
Also its given that
BL ≅PF
The angle opposite BL is ∠G
The angle opposite PF is ∠X
∠G ≅ ∠X
Again
BG ≅PX
The angle opposite BG is ∠L
The angle opposite PX is ∠F
So ∠L ≅ ∠F
Hence B in place of P
L in place of F
G in place of X
So for ΔPFX, the corresponding triangle is ΔBLG
Hence
ΔBLG ≅ ΔPFX
