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  • 18-09-2018
  • Mathematics
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PLEASE HELP!!!!!! Will give brainliest to who is correct

Solve for x over the complex numbers.

x^2+10x+41=0

x =_____ or x=____

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Аноним Аноним
  • 18-09-2018

x²+10x+41=0

using x=(-b±√b²-4ac)½

where a= 1

b=10

c=41


x= (-10±√10²-4×1×41)½

x=-5 ± √(100-164)

x=-5±√(-64)½

x=-5±4i

x=-5+4i or -5-4i  

where i= √-1

ANSWER: x=-5+4i or -5-4i  

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