Hey guys, I'm really stuck with this problem. A dozen golf balls fit inside a box in the shape of a rectangular prism. The golf balls are packed tightly together and they touch the top, bottom and sides of the box. What percentage of the volume within the box is air? Please show work.
ok so one way of doingit is split the box into 12 cubes around each golf ball nnow find the wasted space that each golf ball wastes around itself since the ratio of the total percent must be the same as the total
so lets say the height of the cubes=2 so therefor volume of each cube=2^3=8
now find the volume of each apere volume=4/3pir^3 the height=diameter diameter/2=radius 2/2=1=radius volumeofsphere=4/3pi1^3 vs=4/3pi1 vs=4/3pi aprox pi to 3.14 vs=12.56/3 vs=4.18666
so now we have total space=8 area of ball=4.186666 percent lost=total-areauseed=8-4.18666=3.81333333 so percent lost=lost/total=3.81333/8=0.397/1 percent means parts out of 100 0.397/1 times 100/100=39.7/100=39.7%
