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Write the equation of the line in slope-intercept form, slope is 5 and (2,6) is on the line

Respuesta :

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{6})\qquad \qquad \qquad slope = m\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-6=5(x-2) \\\\\\ y-6=5x-10\implies y=5x-4[/tex]
choixongdong

slope-intercept form:

y = mx + b where m = slope and b = y intercept


given slope m = 5 , now you need to find b


passing thru (2,6)

using y = mx + b to find b


y = mx + b

b = y - mx

b = 6 - (5)(2)

y = 6 - 10

y = -4


Now you know m = 5 and b = -4


Equation:

y = 5x - 4

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