cyndiejoseph536 cyndiejoseph536
  • 19-07-2018
  • Mathematics
contestada

The law of cisines is a +b+c -abcosC=c find the value of2abcosC

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qabtt
qabtt qabtt
  • 19-07-2018

The law of cosines says [tex] c^2 = a^2 + b^2 - 2abc\cos C [/tex].


Given this, we can add [tex] 2ab\cos C [/tex] to the both sides and subtract [tex] c^2 [/tex] from the both sides to get the equation [tex] 2ab\cos C = a^2 + b^2 - c^2 [/tex].


Thus, the value of [tex] 2ab\cos C [/tex] is [tex] \boxed{a^2 + b^2 - c^2} [/tex].

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Аноним Аноним
  • 19-07-2018

{a^2 + b^2 - c^2} is the final answer!

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