Respuesta :

Chlidonias

Mass % of NaCl = 0.9 % (m/v)

Density of 0.9 % NaCl is about 1.0 g/mL

Volume of NaCl in mL :

[tex] 1.25 L solution * \frac{1000 mL}{1 L} * \frac{0.9 g NaCl}{100 mL solution}*\frac{1 mL}{1.0 g NaCl} [/tex]

= 11.25 mL NaCl

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