Blue8004 Blue8004
  • 18-07-2018
  • Mathematics
contestada

Find an equation of the circle that has center (-4, 1) and passes through (3, -5)

Respuesta :

DeanR
DeanR DeanR
  • 18-07-2018

The general equation for a circle with center (a,b) and squared radius k is


[tex](x-a)^2 + (y-b)^2 = k[/tex]


Here we have


[tex](x- - 4)^2 + (y -1)^2 = k[/tex]


and the constant is fixed by substituting in the point we know (x,y)=(3,-5)


[tex](x + 4)^2 + (y-1)^2 = (3+4)^2 + (-5-1)^2 = 85[/tex]


Answer:


[tex](x + 4)^2 + (y-1)^2 = 85[/tex]


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