Respuesta :

caylus
Hello,

Answer A.

[tex]x^2+2x=15\\ \Rightarrow\ x^2+2x-15=0\\ \Rightarrow\ x^2+2x+1-16=0\\ \Rightarrow\ (x+1)^2-4^2=0\\ \Rightarrow\ (x+1-4)(x+1+4)=0\\ \Rightarrow\ (x-3)(x+5)=0\\ \boxed{\Rightarrow\ x=3\ or\ x=-5} [/tex]

maddymcg408

Answer:

A.    3 AND -5

Step-by-step explanation:

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