step 1 we know that It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively. Therefore, x = ∠CAB/2 -----> equation 1 y = ∠CBA/2 -----> equation 2
step 2 In triangle ABC, ∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a
triangle is 180°] ∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides ∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3 substitute equation 1 and equation 2 in equation 3 x+y=35
hence
the answer is x+y =35° ⇒ x + y = 35° ...[From equation (1) and (2)]
