gekiyasmith321 gekiyasmith321

16-06-2018
Mathematics

contestada

the measure of c is
A.
[tex] 16\sqrt{13} [/tex]
B.
[tex] \sqrt{208} [/tex]
C.
[tex] 4\sqrt{13} [/tex]
D.
[tex]8 \sqrt{13} [/tex]

the measure of c isA tex 16sqrt13 texB tex sqrt208 texC tex 4sqrt13 texD tex8 sqrt13 tex class=

Respuesta :

jamesmacnab3owy6vd jamesmacnab3owy6vd

16-06-2018

4√13
64+144=208
208÷16=13
8²=64
12²=144
4²=16

Answer Link

sqdancefan sqdancefan

16-06-2018

By the Pythagorean theorem,
c² = 8² + 12²
c² = 64 + 144 = 208
c = √(208) = √(16×13)
c = (√16)(√13) = 4√13

The best choice is
[tex]C.\quad4\sqrt{13}[/tex]

Answer Link

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