LucyMackin
LucyMackin LucyMackin
  • 20-05-2018
  • Mathematics
contestada

How do you find the x-intercepts of
[tex]y = 12x + {7x}^{2} [/tex]
Please help!!

Respuesta :

gmany
gmany gmany
  • 27-05-2018
x - intercepts → y = 0

[tex]y=12x+7x^2\to12x+7x^2=0\\\\x(12+7x)=0\iff x=0\ \vee\ 12+7x=0\\\\x=0\ \vee\ 7x=-12\\\\x=0\ \vee\ x=-\dfrac{12}{7}[/tex]

Answer: [tex]x=0;\ x=-\dfrac{12}{7}[/tex]
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