bri469 bri469
  • 16-05-2018
  • Mathematics
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R=2.3log(A+300)-5.1 solve for A in terms of R

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gmany
gmany gmany
  • 16-05-2018
[tex]2.3\log(A+300)-5.1=R\ \ \ \ |+5.1\\\\2.3\log(A+300)=R+5.1\ \ \ |:2.3\\\\\log(A+300)=\dfrac{R+5.1}{2.3}\iff A+300=10^{\frac{R+5.1}{2.3}}\ \ \ |-300\\\\\boxed{A=10^{\frac{10R+51}{23}}-300}[/tex]
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