lhyavandenbulke lhyavandenbulke
  • 18-01-2023
  • Mathematics
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1/ = 7 × (16 − (2 + 9)) 2/ = (9 − (9 − 8)) × ((2 + 7) ÷ 3) 3/ = 4 × (39,5 − (2,4 + 4,8) + 3) 4/ = 120 ÷ [((66 − (25 + 8 − 7)) ÷ 2 + 3]

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